2. Directions: Answer (A) if the quantity in Column A is greater; (B) if the quantity in Column B is greater; (C) if the two quantities are equal, or (D) if the relationship cannot be determined¹ from the information given

　　Square A has sides of length x and square B has sides of twice this length.

　　Column A

　　Area of square A

　　Column B

　　Half the area of square B

　　Answers and Explanations

　　1. The correct answer is (C). Since we are not given a number for how many subscriptions² Gina sold in April, let’s pick a number. Let’s pick 100. When you have a percent problem and numbers are not provided, you should always pick 100 because it is easy to work with.

　　In April, let’s say Gina sold 100 magazines. We are told that in May she sold 40 percent more magazine subscriptions than she had in April so the number she sold in May is 100 plus 40 percent of 100, or 140. In June, Gina sold 20 percent more subscriptions than she did in May. Well, in May she sold 140 subscriptions and 20 percent of 140 is 20 percent times 140 or 28.

　　Therefore, in June, Gina sold 140 plus 28 subscriptions, or 168 subscriptions. The percent that the number of magazine subscriptions sold in June, 168, is greater than the number sold in April, 100, is 68 percent, answer choice(C).

　　2. The correct answer is (B). In this question, we are given that one square, A, has sides of length x and a second square, B, has sides of twice this length (or 2x), and we are asked to compare the area of A to one half the are a of B. The first thing you should do is draw a diagram. (You should draw a　diagram when you are not provided with one or when you are given one that is not drawn³ to scale.) If you draw the squares somewhat carefully, the answer becomes obvious.

　　Figured out mathematically, the area of a square is the side squared. Column A will, then, yield a square with area x2. Column B will yield a square with area 4x2. x2 compared to 2x2 gives us an answer choice of (B) because 2x2 is greater. You could have picked numbers for the sides of the squares and would have still come out with Column B being greater.